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The dataset generation failed
Error code: DatasetGenerationError
Exception: IndexError
Message: list index out of range
Traceback: Traceback (most recent call last):
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1859, in _prepare_split_single
original_shard_lengths[original_shard_id] += len(table)
~~~~~~~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^
IndexError: list index out of range
The above exception was the direct cause of the following exception:
Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1369, in compute_config_parquet_and_info_response
parquet_operations, partial, estimated_dataset_info = stream_convert_to_parquet(
~~~~~~~~~~~~~~~~~~~~~~~~~^
builder, max_dataset_size_bytes=max_dataset_size_bytes
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
)
^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 948, in stream_convert_to_parquet
builder._prepare_split(split_generator=splits_generators[split], file_format="parquet")
~~~~~~~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1694, in _prepare_split
for job_id, done, content in self._prepare_split_single(
~~~~~~~~~~~~~~~~~~~~~~~~~~^
gen_kwargs=gen_kwargs, job_id=job_id, **_prepare_split_args
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
):
^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1880, in _prepare_split_single
raise DatasetGenerationError("An error occurred while generating the dataset") from e
datasets.exceptions.DatasetGenerationError: An error occurred while generating the datasetNeed help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.
prompt_id string | sample_index int64 | model_id string | thinking string | answer string | verdict string | n_passed int64 | n_total int64 | n_attempted int64 | finish_reason string | verifier_kind string |
|---|---|---|---|---|---|---|---|---|---|---|
367188573f5ca8ab | 0 | Qwen/Qwen3.8-27B | We need to respond to user: Convert given for loop to functional programming approach with recursion. Function should include error handling for non-integer list items. Answer must contain a title wrapped in double angular brackets, such as <<poem of joy>>. Must contain exactly 1 bullet points. Use markdown bullet poin... | <<Recursive Doubling with Error Handling>>
* Python solution:
```python
def double_list(items):
if not items:
return []
item = items[0]
if not isinstance(item, int) or isinstance(item, bool):
raise TypeError("All list items must be integers")
return [item.__mul__(2)] + double_list(items[... | pass | 2 | 2 | 8 | stop | ifeval_spec |
367188573f5ca8ab | 1 | Qwen/Qwen3.8-27B | We need respond to user. Need produce final with exactly 1 bullet point, and title wrapped in double angular brackets. User asks convert for loop to functional programming approach with recursion, error handling for non-integer list items. Need include code likely Python. Must contain exactly 1 bullet point. So final s... | <<Recursive Functional List Doubling>>
* Use this pure recursive function, which replaces the loop and raises a clear error for non-integer items:
```python
def double_numbers(items):
if not items:
return []
item = items[0]
if not isinstance(item, int) or isinstance(item, bo... | pass | 2 | 2 | 8 | stop | ifeval_spec |
367188573f5ca8ab | 2 | Qwen/Qwen3.8-27B | We need answer user's request. Need produce final with title wrapped double angular brackets, exactly 1 bullet points. User asks: Convert given for loop code to functional programming approach with recursion. Function should also include error handling for non-integer list items.
Input code:
list = [1,2,3,4]
for i in l... | <<Functional Recursive Doubling>>
* ```python
def double_values(lst, i=0):
if i == len(lst):
return []
item = lst[i]
if type(item) is not int:
raise TypeError("non-integer item")
return [item * 2] + double_values(lst, i + 1)
result = double_values([1, 2, 3, 4])
``` | pass | 2 | 2 | 8 | stop | ifeval_spec |
367188573f5ca8ab | 3 | Qwen/Qwen3.8-27B | We need to respond to user: Convert given for loop to functional programming approach with recursion. Include error handling for non-integer list items. Must contain a title wrapped in double angular brackets, e.g. <<poem of joy>>. Must contain exactly 1 bullet points. Use markdown bullet points such as:
* This is poin... | <<Recursive Functional Doubling>>
* The recursive functional equivalent is:
```python
def double_list(items):
if not items:
return []
first = items[0]
if isinstance(first, bool) or not isinstance(first, int):
raise ValueError(f"Non-integer item found: {first!r}")
return [first * 2] + do... | pass | 2 | 2 | 8 | stop | ifeval_spec |
367188573f5ca8ab | 4 | Qwen/Qwen3.8-27B | We need answer user: Convert given for loop code to functional programming approach with recursion. Include error handling for non-integer list items. Answer must contain a title wrapped in double angular brackets, e.g. <<poem of joy>>. Must contain exactly 1 bullet point. Use markdown bullet points such as:
* This is ... | <<Recursive Functional Doubling>>
* Code:
```python
def double_values(items, index=0, accumulator=()):
if index == len(items):
return list(accumulator)
item = items[index]
if not isinstance(item, int) or isinstance(item, bool):
raise TypeError(f"Non-integer item at index {inde... | pass | 2 | 2 | 8 | stop | ifeval_spec |
367188573f5ca8ab | 5 | Qwen/Qwen3.8-27B | We need respond to user: "Convert the given for loop code to a functional programming approach with recursion. The function should also include error handling for non-integer list items.
list = [1,2,3,4]
for i in list:
new_list.append(i * 2) Your answer must contain a title, wrapped in double angular brackets, such... | <<Recursive Doubling with Integer Validation>>
* Here is the recursive function:
```python
def double_values(numbers, index=0):
if index == len(numbers):
return []
value = numbers[index]
if not isinstance(value, int) or isinstance(value, bool):
raise ValueError("All list items ... | pass | 2 | 2 | 8 | stop | ifeval_spec |
367188573f5ca8ab | 6 | Qwen/Qwen3.8-27B | We need to respond to user: "Convert the given for loop code to a functional programming approach with recursion. The function should also include error handling for non-integer list items.
list = [1,2,3,4]
for i in list:
new_list.append(i * 2) Your answer must contain a title, wrapped in double angular brackets, s... | <<Recursive Functional List Doubling>>
* Use this recursive functional version:
```python
def double_list(items):
if not items:
return []
value = items[0]
if not isinstance(value, int) or isinstance(value, bool):
raise ValueError("List items must be integers")
return [val... | pass | 2 | 2 | 8 | stop | ifeval_spec |
367188573f5ca8ab | 7 | Qwen/Qwen3.8-27B | We need to respond to user: "Convert the given for loop code to a functional programming approach with recursion. The function should also include error handling for non-integer list items.
list = [1,2,3,4]
for i in list:
new_list.append(i * 2) Your answer must contain a title, wrapped in double angular brackets, s... | <<Recursive Functional List Doubling>>
* This recursive function uses an immutable tuple accumulator to double each integer and handles non-integer list items by raising an error.
```python
def double_list(items, acc=()):
if not isinstance(items, (list, tuple)):
raise TypeError("Input must be a list or tup... | pass | 2 | 2 | 8 | stop | ifeval_spec |
43028742df18769a | 0 | Qwen/Qwen3.8-27B | We need solve geometry problem. Need provide final answer with step-by-step. Need think carefully.
Problem: Tetrahedron ABCD. Edge AB length 3 cm. Area of face ABC = 15 cm^2. Area of face ABD = 12 cm^2. These two faces meet each other at a 30° angle. Find volume.
We need volume tetrahedron. Two faces share edge AB. D... | Let the common edge be \(AB=3\).
For face \(ABC\),
\[
[ABC]=\frac12(AB)(h_C)
\]
so the perpendicular distance from \(C\) to line \(AB\) is
\[
h_C=\frac{2[ABC]}{AB}=\frac{2\cdot 15}{3}=10.
\]
Similarly, for face \(ABD\),
\[
h_D=\frac{2[ABD]}{AB}=\frac{2\cdot 12}{3}=8.
\]
Now take a cross-section perpendicular to ... | pass | 1 | 1 | 8 | stop | math_answer |
43028742df18769a | 1 | Qwen/Qwen3.8-27B | We need solve geometry problem step by step. Need final answer. Let's analyze thoroughly.
Problem: Tetrahedron ABCD. Edge AB length 3 cm. Area of face ABC = 15 cm^2, area of face ABD = 12 cm^2. These two faces meet at a 30° angle. Find volume.
We need compute volume. Faces ABC and ABD share edge AB. Their areas given... | Let \(AB\) be the common edge of the two faces.
For face \(ABC\), using base \(AB=3\):
\[
15=\frac12(3)(h_C)
\]
\[
h_C=10
\]
So the perpendicular distance from \(C\) to line \(AB\) within face \(ABC\) is \(10\) cm.
For face \(ABD\), similarly:
\[
12=\frac12(3)(h_D)
\]
\[
h_D=8
\]
So the perpendicular distance f... | pass | 1 | 1 | 8 | stop | math_answer |
43028742df18769a | 2 | Qwen/Qwen3.8-27B | We need solve geometry problem. Need produce step-by-step final with Answer: ... We need ensure correctness. Let's analyze thoroughly.
Problem: Tetrahedron ABCD, edge AB length 3. Area of face ABC = 15 cm^2, face ABD = 12 cm^2. These two faces meet at 30° angle. Find volume.
We need compute volume. Tetrahedron volume... | Let \(h_D\) be the perpendicular distance from \(D\) to edge \(AB\) within face \(ABD\).
Since the area of \(\triangle ABD\) is \(12\text{ cm}^2\) and \(AB=3\text{ cm}\),
\[
12=\frac12(3)h_D
\]
so
\[
h_D=8\text{ cm}.
\]
The faces \(ABC\) and \(ABD\) meet at a \(30^\circ\) dihedral angle along \(AB\). Therefore, th... | pass | 1 | 1 | 8 | stop | math_answer |
43028742df18769a | 3 | Qwen/Qwen3.8-27B | We need solve geometry problem. Need produce final with step-by-step and Answer line.
Problem: Tetrahedron ABCD, edge AB length 3. Areas of faces ABC and ABD are 15 and 12. These two faces meet at 30° angle (dihedral angle along AB presumably). Find volume.
We need derive. Tetrahedron with common edge AB. Faces ABC a... | Let the common edge of the two faces be \(AB\), with
\[
AB=3.
\]
The area of \(\triangle ABC\) is \(15\), so its altitude from \(C\) to \(AB\) is
\[
h_C=\frac{2\cdot 15}{3}=10.
\]
Similarly, the area of \(\triangle ABD\) is \(12\), so its altitude from \(D\) to \(AB\) is
\[
h_D=\frac{2\cdot 12}{3}=8.
\]
The two f... | pass | 1 | 1 | 8 | stop | math_answer |
43028742df18769a | 4 | Qwen/Qwen3.8-27B | We need solve problem. Need provide step-by-step. Let's reason.
We have tetrahedron ABCD. Edge AB length 3. Areas of faces ABC and ABD are 15 and 12. These two faces meet at 30° angle. Find volume.
We need interpret: faces ABC and ABD share edge AB. The dihedral angle between them is 30°. Given areas of triangles on ... | Let the common edge \(AB\) be the line where the two faces meet.
1. Since \(AB=3\) and the area of \(\triangle ABC\) is \(15\),
\[
15=\frac12(3)(h_C)
\]
where \(h_C\) is the perpendicular distance from \(C\) to line \(AB\). Thus,
\[
15=\frac32 h_C \implies h_C=10.
\]
2. Similarly, since the area of \(\triangle ABD... | pass | 1 | 1 | 8 | stop | math_answer |
43028742df18769a | 5 | Qwen/Qwen3.8-27B | We need solve geometry. Need provide final answer with Answer: line. Need reason carefully.
Problem: Tetrahedron ABCD, edge AB length 3 cm. Areas of faces ABC and ABD are 15 and 12 cm^2. These two faces meet at 30° angle. Find volume.
We need step-by-step.
Interpretation: two faces ABC and ABD share edge AB. Their d... | Let the common edge \(AB\) be used as the base for the two triangular faces.
For face \(ABC\), let \(h_C\) be the altitude from \(C\) to \(AB\). Then
\[
[ABC]=\frac12(AB)(h_C)
\]
\[
15=\frac12(3)h_C \implies h_C=10.
\]
For face \(ABD\), let \(h_D\) be the altitude from \(D\) to \(AB\). Then
\[
[ABD]=\frac12(AB)(h_... | pass | 1 | 1 | 8 | stop | math_answer |
43028742df18769a | 6 | Qwen/Qwen3.8-27B | We need solve geometry. Now analysis. Problem: tetrahedron ABCD, edge AB length 3. Areas of faces ABC=15, ABD=12. These two faces meet at 30° angle. Find volume.
We need be careful: two triangular faces sharing edge AB. Their areas are given. Dihedral angle between faces along AB is 30°. Volume of tetrahedron can be c... | Let \(h_C\) be the perpendicular distance from \(C\) to edge \(AB\). Since
\[
[ABC]=\frac12(AB)(h_C),
\]
we have
\[
15=\frac12(3)(h_C)\implies h_C=10.
\]
Similarly, let \(h_D\) be the perpendicular distance from \(D\) to edge \(AB\). Then
\[
12=\frac12(3)(h_D)\implies h_D=8.
\]
Now use face \(ABC\) as the base of... | pass | 1 | 1 | 8 | stop | math_answer |
43028742df18769a | 7 | Qwen/Qwen3.8-27B | We need solve geometry problem. Need provide step by step and final Answer: value. Let's analyze thoroughly.
Problem: Tetrahedron ABCD. Edge AB length 3 cm. Area of face ABC =15 cm^2, area face ABD=12 cm^2. These two faces meet at 30° angle. Find volume.
We need determine volume from common edge and adjacent face are... | Let \(AB=3\) cm.
The area of \(\triangle ABC\) is given by
\[
[ABC]=\frac12(AB)(h_C)
\]
where \(h_C\) is the perpendicular distance from \(C\) to line \(AB\) in face \(ABC\). Thus
\[
15=\frac12(3)h_C
\]
\[
h_C=10.
\]
Similarly, for \(\triangle ABD\),
\[
12=\frac12(3)h_D
\]
\[
h_D=8.
\]
The two faces meet along... | pass | 1 | 1 | 8 | stop | math_answer |
19b89dfb61d1babc | 0 | Qwen/Qwen3.8-27B | We need solve math problem. Need provide final answer with last line Answer: $Answer. Need think carefully.
Problem: How many positive perfect squares less than 10^6 are multiples of 24?
We need count n positive integers such that n^2 < 10^6, 24 | n^2. n^2 perfect square positive less than 1,000,000. n positive integ... | Let the perfect square be \(n^2\), where \(n\) is a positive integer.
We need
\[
n^2 < 10^6
\]
so
\[
n < 1000
\]
Thus \(n\) can be any positive integer from \(1\) to \(999\).
Now we require \(n^2\) to be a multiple of \(24\). Factor:
\[
24 = 2^3 \cdot 3
\]
For \(24\) to divide \(n^2\), the square \(n^2\) must c... | pass | 1 | 1 | 8 | stop | math_answer |
19b89dfb61d1babc | 1 | Qwen/Qwen3.8-27B | We need solve math problem. Need produce final answer with step-by-step and last line Answer: $Answer. Let's reason carefully.
Problem: How many positive perfect squares less than 10^6 are multiples of 24?
We need count n^2 positive integer squares, n^2 < 1,000,000, divisible by 24.
24 = 2^3 * 3. For n^2 to be divis... | We need positive perfect squares \(n^2 < 10^6\) that are multiples of \(24\).
Factor \(24\):
\[
24 = 2^3 \cdot 3
\]
For a perfect square \(n^2\) to be divisible by \(2^3\), its factor of \(2\) must have exponent at least \(3\). But exponents in a perfect square are even, so it must actually be divisible by \(2^4\).
... | pass | 1 | 1 | 8 | stop | math_answer |
19b89dfb61d1babc | 2 | Qwen/Qwen3.8-27B | We need answer math problem step by step. Need solve. Problem: How many positive perfect squares less than 10^6 are multiples of 24?
We need count n^2 < 1,000,000, positive integer n, such that 24 | n^2. n^2 multiple of 24 = 2^3 * 3. For square to be divisible by 24, its prime exponents at least 3 for 2 and 1 for 3, b... | We want positive perfect squares \(n^2 < 10^6\) that are multiples of \(24\).
Since \(24 = 2^3 \cdot 3\), a square must have even prime exponents. For \(n^2\) to be divisible by \(2^3\), it must actually be divisible by \(2^4\). For divisibility by \(3\), it must actually be divisible by \(3^2\). Thus \(n^2\) must be ... | pass | 1 | 1 | 8 | stop | math_answer |
19b89dfb61d1babc | 3 | Qwen/Qwen3.8-27B | We need solve math problem step by step. Let's reason. Problem: How many positive perfect squares less than 10^6 are multiples of 24?
Need count n^2 positive < 10^6, 24 | n^2.
We can analyze prime factorization 24=2^3 * 3. For n^2 to be divisible by 2^3*3. Let n have primes. n^2 exponents even. Need exponent of 2 in ... | We need to count positive perfect squares of the form \(n^2\) such that
\[
n^2 < 10^6
\]
and \(24\) divides \(n^2\).
Factor \(24\):
\[
24 = 2^3 \cdot 3
\]
For \(24 \mid n^2\), the square \(n^2\) must have at least three factors of \(2\) and at least one factor of \(3\).
Let \(n\) have prime factorization. Since e... | pass | 1 | 1 | 8 | stop | math_answer |
19b89dfb61d1babc | 4 | Qwen/Qwen3.8-27B | We need solve problem. Need provide final with Answer: ... Let's reason carefully.
Problem: How many positive perfect squares less than 10^6 are multiples of 24?
We need count n^2 < 1,000,000 = 1000^2? Actually 10^6 = 1,000,000, positive perfect squares less than 10^6, so squares n^2 with n positive integer, n^2 < 1,... | We need to count positive perfect squares \(n^2 < 10^6\) that are multiples of \(24\).
A square is a multiple of \(24 = 2^3 \cdot 3\) only if it is actually a multiple of the smallest square containing those factors:
\[
24 \mid n^2 \iff 2^4 \cdot 3^2 \mid n^2 \iff 144 \mid n^2.
\]
Since \(144 = 12^2\), this means \(... | pass | 1 | 1 | 8 | stop | math_answer |
19b89dfb61d1babc | 5 | Qwen/Qwen3.8-27B | We need solve math problem step by step. Need provide final answer format. Let's think carefully.
Problem: How many positive perfect squares less than 10^6 are multiples of 24?
We need count n^2 such that 0 < n^2 < 1,000,000 and 24 | n^2.
n positive integer, n^2 < 10^6 => n < 1000 (since 1000^2=1e6 not less). So n =... | Let the perfect square be \(n^2\), where \(n\) is a positive integer.
Since \(n^2 < 10^6\),
\[
n^2 < 1000000 \implies n < 1000.
\]
So \(n\) can be any positive integer from \(1\) to \(999\).
We need \(n^2\) to be a multiple of \(24\). Factor \(24\):
\[
24 = 2^3 \cdot 3.
\]
For \(n^2\) to be divisible by \(2^3\), ... | pass | 1 | 1 | 8 | stop | math_answer |
19b89dfb61d1babc | 6 | Qwen/Qwen3.8-27B | We need answer math problem. Need solve step by step, final line Answer: $Answer. Problem: How many positive perfect squares less than 10^6 are multiples of 24?
We need count positive perfect squares n^2 < 1,000,000, divisible by 24. Since n^2 < 10^6 = (1000)^2, positive n <=999. Need n^2 divisible by 24. 24=8*3. For ... | We need to count positive perfect squares less than \(10^6\) that are multiples of \(24\).
A positive perfect square can be written as \(n^2\), where \(n\) is a positive integer. Since
\[
n^2 < 10^6 = 1000^2,
\]
we must have
\[
n \le 999.
\]
Now we require \(n^2\) to be a multiple of \(24\). Factor:
\[
24 = 2^3 \... | pass | 1 | 1 | 8 | stop | math_answer |
19b89dfb61d1babc | 7 | Qwen/Qwen3.8-27B | We need solve math problem. done. Need produce final with step-by-step and last line Answer: $Answer. Need careful.
Problem: How many positive perfect squares less than 10^6 are multiples of 24?
We need count positive perfect squares n^2 < 1,000,000 that are divisible by 24.
Let n positive integer, n^2 < 10^6 => n <... | Let the perfect square be \(n^2\), where \(n\) is a positive integer.
We need
\[
n^2 < 10^6
\]
which means
\[
n < 1000.
\]
So \(n\) can range from \(1\) to \(999\).
Now require \(n^2\) to be a multiple of \(24\). Since
\[
24 = 2^3 \cdot 3,
\]
we need \(n^2\) to be divisible by \(2^3\) and \(3\).
For \(n^2\) to... | pass | 1 | 1 | 8 | stop | math_answer |
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